Question
450 litres of mixture βAβ contains milk and water
in it. If mixture βAβ is mixed with 750 litres of mixture βBβ which contains water and salt, then the ratio of quantity of milk, water and salt in the final mixture will be 5:9:6, respectively. Find the difference between quantity of water in mixture βAβ and mixture βBβ.Solution
Total quantity of mixture = 450 + 750 = 1200 litres Quantity of milk in final mixture = (5/20) Γ 1200 = 300 litres Quantity of water in mixture βAβ = 450 β 300 = 150 litres Quantity of salt in mixture βBβ = (6/20) Γ 1200 = 360 litres Quantity of water in mixture βBβ = 750 β 360 = 390 litres Required difference = 390 β 150 = 240 litres
(0.125)³÷ (0.25)² x (0.5)² = (0.5)?-3
54 - 78 + 1518 + 1653 – 1252 = ?
In the question, two Quantities I and II are given. You have to solve both the Quantity to establish the correct relation between Quantity-I and Quantit...
22% of 280 + 34% of 1080 × 5/12 =? + 16% of 460
800 + 900 X (3)-2 - ? = 25 X 60 Γ· 2Β
What value should come in the place of (?) in the following questions?
β289 * 2 +3β729 * 3 + 24 Γ· 8 = ?2
Evaluate:
7.5 + 12 Γ· (4 Γ 1.5) β 2.4
β? = 120 - 102 + β125
Simplify: 48 Γ· 4 Γ 3 + 5 Γ (6 β 2)
√4761 ÷ 23 + √12769 = ? × 58