Question
450 litres of mixture ‘A’ contains milk and water
in it. If mixture ‘A’ is mixed with 750 litres of mixture ‘B’ which contains water and salt, then the ratio of quantity of milk, water and salt in the final mixture will be 5:9:6, respectively. Find the difference between quantity of water in mixture ‘A’ and mixture ‘B’.Solution
Total quantity of mixture = 450 + 750 = 1200 litres Quantity of milk in final mixture = (5/20) × 1200 = 300 litres Quantity of water in mixture ‘A’ = 450 − 300 = 150 litres Quantity of salt in mixture ‘B’ = (6/20) × 1200 = 360 litres Quantity of water in mixture ‘B’ = 750 − 360 = 390 litres Required difference = 390 − 150 = 240 litres
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