Question
A mixture is prepared by combining three ingredients M,
N, and O in the ratio of 5:4:3. Ingredient M contains 60% sugar, N contains 50% sugar, and O contains 40% sugar. Find the percentage of sugar in the mixture.Solution
Let the volumes of M, N, and O be 5x, 4x, and 3x liters respectively. Total volume = 5x + 4x + 3x = 12x liters Sugar in M = 5x Ă— 0.60 = 3.00x liters Sugar in N = 4x Ă— 0.50 = 2.00x liters Sugar in O = 3x Ă— 0.40 = 1.20x liters Total sugar = 3.00x + 2.00x + 1.20x = 6.20x liters Percentage of sugar = (6.20x / 12x) Ă— 100 = 51.67% The percentage of sugar in the mixture is approximately 52%. Correct Option: b
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