Question
A container has 40 litres of a solution containing 25%
alcohol. How many litres of pure alcohol must be added so that the resulting mixture contains 40% alcohol?Solution
ATQ, Alcohol in original solution = 25% of 40 = 10 litres. Let x litres of pure alcohol be added. Total alcohol after mixing = 10 + x Total volume = 40 + x Required concentration = 40% ⇒ (10 + x) / (40 + x) = 0.4 10 + x = 0.4(40 + x) 10 + x = 16 + 0.4x x − 0.4x = 16 − 10 0.6x = 6 ⇒ x = 10 litres.
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