Question
A liquid consists of acid and water in the ratio 5:3. If 20
ml of the mixture is removed and replaced with 10 ml of acid, the new ratio becomes 5:2. Find the initial quantity of the liquid.Solution
ATQ,
Let acid and water left after removing 20 ml of the mixture be 5x ml and 3x ml respectively.
Acid after addition = (5x + 10) ml
ATQ,
(5x + 10) / 3x = 5/2
⇒ 10x + 20 = 15x
⇒ 15x - 10x = 20
⇒ 5x = 20
⇒ x = 4
So, initial quantity = 5×4 + 3×4 + 20 = 20 + 12 + 20 = 52 ml
6   55   91   116   132    ?  . Â
98    219    75    244    ?    273
Select the option in which the numbers are related in the same way as are the numbers of the following set.
(25, 18, 225)
26 63 124 215 342 511 ?
...8 9 30 155 ? 9837 108218
...3,   2,   3,  8,  31,  ?
3 12 48 192 768 ?
104Â Â Â Â Â Â 156Â Â Â Â Â Â Â 234Â Â Â Â Â Â Â ? Â Â Â Â Â Â Â 526.5Â Â Â Â Â Â Â 789.75
...18, 32, 50, 82, 132, ?
5Â Â Â Â 10Â Â Â Â Â 30Â Â Â Â Â 150Â Â Â Â Â 950Â Â Â Â Â 11550
...
