Question
A mixture (milk + water + honey) contains ‘16m’
litres milk, ‘24n’ litres water and 56 litres more honey than water. If 25% of the mixture was replaced with 8 litres of milk, then the quantity of water in the resultant mixture becomes 10% less than that of milk. Instead, if 25% of the mixture is replaced with 96 litres of honey, then the ratio of the quantity of milk to that of honey will become 1:2. Find the initial quantity of water in the mixture.Solution
According to the question, If 25% of the mixture was replaced with 8 litres of milk, then the quantity of milk in the resultant mixture = 16m × 0.75 + 8 = (12m + 8) litres. If 25% of the mixture was replaced with 8 litres of milk, then the quantity of water in the resultant mixture = 24n × 0.75 = ‘18n’ litres. ATQ; (12m + 8) × 0.90 = 18n Or, 12m + 8 = 18n ÷ 0.9 = 20n So, 12m = (20n – 8) – [equation I] If 25% of the mixture was replaced with 96 litres of honey, then the quantity of milk in the resultant mixture = 16m × 0.75 = ‘12m’ litres. If 25% of the mixture was replaced with 96 litres of honey, then the quantity of honey in the resultant mixture = (24n + 56) × 0.75 + 96 = 18n + 42 + 96 = (18n + 138) litres. So, 12m:(18n + 138) = 1:2 Or, 24m = 18n + 138 – [equation II] Multiplying equation (I) by ‘2’, we have: 24m = (40n – 16) So, (40n – 16) = (18n + 138) [from equation 2] Or, 22n = 154 So, n = 154 ÷ 22 ≈ 7 Therefore, the initial quantity of water in the mixture = 24 × 7 = 168 litres.
30% of 200 – 20% of 50 = 10% of ?
?3 - 25 × 11 = 30 - 15 × 12
Simplify the following expressions and choose the correct option.
(45% of 640) ÷ 8 + (3/4 of 96) = ?
- What will come in the place of question mark (?) in the given expression?
(15 - 19 + 10) ² + ? = 45 X 2 - 48% of 300 – 24% of 150 = 12% of ?
36% of 250 + 26 ÷ 2 × ? = 207
10 × 100 ÷ 5 + 9 = ?
What will come in the place of question mark (?) in the given expression?
? = (27 × 13) – 26% of (412 – 92 )
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