Question
A container initially holds 120 litres of pure alcohol.
First, 18 litres of alcohol is removed and replaced with an equal quantity of water. Then, 18 litres of the resulting mixture is removed and replaced again with the same quantity of water. Determine the amount of water currently present in the mixture.Solution
Quantity of alcohol left in the mixture = 120 X {1 - (18/120) }2Â = 86.7 litres So, quantity of water left = 120 - 86.7 = 33.3 litres
More Mixture Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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