Question
Mixture 1 with a volume of 8 liters has 80% milk and
Mixture 2 with a volume of 7 liters has 70% milk. Both the mixtures are mixed. Find the percentage of milk in the final mixture.Solution
Mixture 1- Volume 8 liters, Milk = 80% =8 x 0.80 =6.4 liters Mixture 2: Volume 7 liters, Milk = 70% =7 x 0.70 =4.9 liters Total volume=8+7 =15 liters Total milk=6.4+4.9 =11.3 liters Percentage of milk = (11.3/15) ×100 =75.33%
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?