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    Question

    The container has 60 liters of mixture of alcohol and

    water in the ratio of 3:1. If 28 liters of mixture is replaced by water, then what is the ratio of the quantity of alcohol to water in the final mixture?
    A 4:5 Correct Answer Incorrect Answer
    B 2:3 Correct Answer Incorrect Answer
    C 4:7 Correct Answer Incorrect Answer
    D 7:13 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Alcohol in the container = (3/4) ├Ч 60 = 45 liters Water in container = 60 - 45 = 15 liters Alcohol in 28 liters of mixture = 28 ├Ч (3/4) = 21 liters Water in 28 liters of mixture = 28 тАУ 21 = 7 liters Required ratio = (45 тАУ 21) : (15 тАУ 7 + 28) = 2:3

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