Question
A container holds (p + 80) liters
of juice and 'p' liters of water. If 60 liters of juice and (p/2) liters of water are added to this mixture, the quantity of juice becomes 25% greater than the quantity of water. Determine the initial total amount of the mixture in the container.Solution
ATQ, (p + 80 + 60) / (p + (p/2)) = 125/100 (p + 140) / (3p/2) = 5/4 8 × (p + 140) = 15p 15p – 8p = 1120 p = 1120/7 p = 160 The initial quantity of mixture in the Container = 160 + 80 + 160 = 400 liters
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