Question
There is a 99 litres mixture (soda + water), such that
ratio of quantities of soda and water in it is 6:5, respectively. How much quantity of soda should be mixed in this mixture so that the ratio of quantities of soda to that of water will become 9:5?Solution
Quantity of soda in 99 litres of mixture = (6/11) × 99 = 54 litres Quantity of water in 99 litres of mixture = (5/11) × 99 = 45 litres According to question, Water remains same till the end of the process, So final quantity of soda in the mixture = 45 × (9/5) = 81 litres Quantity of soda to be added = 81 – 54 = 27 litres
{(23.65 × 35.12) ÷ 6.97} + 179.86 = ? × 14.76
(16.16 ×  31.98) + 24.15% of 649.99 = ? + 124.34
Find the approximate value of Question mark(?). No need to find the exact value.
24.95 × (36.06 ÷ 6) + 74.95% of 159.89 – √(143.94) × 2....
78% of 1450 + 26² = ? + 1323 ÷ 17
126.003 × 11.987 + 23.04 × 12.96 = ?
6401.23 × `1 3/4` - 352.87 × ? = 10443.789
? = 782.24 + 1276.97 – 4.992 Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
[15.87% of 599.97 + 40.08 × ?] ÷ 4.04 = 8.082.02
Relevant for Exams:
