Question
There is a 99 litres mixture (soda + water), such that
ratio of quantities of soda and water in it is 6:5, respectively. How much quantity of soda should be mixed in this mixture so that the ratio of quantities of soda to that of water will become 9:5?Solution
Quantity of soda in 99 litres of mixture = (6/11) × 99 = 54 litres Quantity of water in 99 litres of mixture = (5/11) × 99 = 45 litres According to question, Water remains same till the end of the process, So final quantity of soda in the mixture = 45 × (9/5) = 81 litres Quantity of soda to be added = 81 – 54 = 27 litres
What value should come in place of (?) in the given expression.
450 ÷ 9 + 75% of 160 − 64 ÷ 4 = ?
2/5 of 3/4 of 7/9 of 14400 = ?
7/3 of 4/5 of 15/56 of ? = 83
[564 + 32 of 18 × 9 ÷ 12 + 162 ] ÷ 4 = ?
What should come in place of (?) question mark in the given expression.
(25% of 320) + (3/8 of 400) − 30 = ?
45% of 360 - 160 + ? = √324
187 ÷ 5 ÷ 0.4 = ? – 24 × 2.4
Find the simplified value of the following expression:
[{12 + (13 × 4 ÷ 2 ÷ 2) × 5 – 8} + 13 of 8]
18 × 15 + 86 – 58 =? + 38
√(24²+285-8²-172) = ?²
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