There is a 99 litres mixture (soda + water), such that ratio of quantities of soda and water in it is 6:5, respectively. How much quantity of soda should be mixed in this mixture so that the ratio of quantities of soda to that of water will become 9:5?
Quantity of soda in 99 litres of mixture = (6/11) × 99 = 54 litres Quantity of water in 99 litres of mixture = (5/11) × 99 = 45 litres According to question, Water remains same till the end of the process, So final quantity of soda in the mixture = 45 × (9/5) = 81 litres Quantity of soda to be added = 81 – 54 = 27 litres
15% of 2400 + (√ 484 – √ 256) = ?
(8.4 × 6.5 ×2.52 )/(5.04 ×3.25 ×2.1) = ?
34 × 2.5 + 6.4 × 1.5 – 4.8 × 1.2 =?
What is the value of 143 + 163 + 183 + … + 303?
18 + 28÷ 4 - 14 = ? - 35
...85% of 620 + ? % of 1082 = 4855
56 x 8 – 65% of 40 = ? + 14 x √625
62.94% of 1800 - 15.03 % of 2400 = ?
1/5 of 6/3 of 3/2 of 1966 = ?
25% of 300 + √(?) = 35% of 600 - 15% of 300
