Question
An alloy contains 50% iron, 30% zinc, and 20% aluminum. How
much iron should be added to 30 kg of the alloy so that the new alloy contains 60% iron?Solution
ATQ,
Quantity of the alloy = 30 kg
Quantity of iron in 30 kg alloy = (0.50 Ă— 30) = 15 kg
Quantity of zinc in 30 kg alloy = (0.30 Ă— 30) = 9 kg
Quantity of aluminum in 30 kg alloy = (0.20 Ă— 30) = 6 kg
Let the quantity of iron to be added be x kg.
According to the question,
Quantity of iron in the new alloy = (Quantity of zinc + Quantity of aluminum)
(15 + x) = (9 + 6)
Or, x = 15 - 15 = 0
No iron needs to be added as it already satisfies the condition.
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