Question
A is cycling at an average speed of 10 km/hr such that
he can reach a certain point at 12 noon. If he cycles at 30 km/hr, then he will reach the destination at 10 a.m. At what speed he should cycle to reach the destination at 11 a.m.Solution
Let the distance to be travelled be βxβ km Time taken when speed is 10 km/hr = (x/10) hours Time taken when speed is 30 km/hr = (x/30) hours According to the question, (x/10) β (x/30) = 2 Or, 3x β x = 2 Γ 30 Or, 2x = 60 Or, x = 30 km Time taken to travel 30 km with speed of 10 km/hr = 30/10 = 3 hours Therefore, he started at 12 β 3 = 9 a.m. Therefore, required speed to reach the destination at 11 a.m. or 2 hours = 30/2 = 15 km/hr
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