Question
Given that x = 80, y = -35 and z = -45, Determine the
value of [(x³ + y³ + z³)/10³]Solution
ATQ;
As (x + y + z) = (80 – 35 – 45) = 0
So, x³ + y³ + z³ = 3xyz
So, (x³ + y³ + z³) = {3 × 80 × (-35) × (-45)} = 378000
So, required value = {(x³ + y³ + z³)/10³} = (378000/1000) = 378
41 28 ? 15 67 2
3 15 35 63 99 ?
4                14                  130                     512                �...
1 1 8 4 27 9 81
...Select the number from among the given options that can replace the question mark (?) in the following series.
24, 35, 51, 73, 102, ?
4 5 12 39 160 ?
...10, 22, 46, ?, 130, 190
3  16  22  ?   98   206
542Â Â Â Â Â Â 541Â Â Â Â Â Â Â 532Â Â Â Â Â Â Â 507 Â Â Â Â Â Â Â 458Â Â Â Â Â Â Â ?
...If   314     306      x      269       394    178    1480
Then, 1/3 x + 2x - x = ?
...
