Question
Given that x = 80, y = -35 and z = -45, Determine the
value of [(x³ + y³ + z³)/10³]Solution
ATQ;
As (x + y + z) = (80 – 35 – 45) = 0
So, x³ + y³ + z³ = 3xyz
So, (x³ + y³ + z³) = {3 × 80 × (-35) × (-45)} = 378000
So, required value = {(x³ + y³ + z³)/10³} = (378000/1000) = 378
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
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³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...