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    Question

    If 10x2 тАУ 6xy+y┬▓ тАУ 4x+4= 0, then find

    the value of (3x+2y).
    A 10 Correct Answer Incorrect Answer
    B 20 Correct Answer Incorrect Answer
    C 14 Correct Answer Incorrect Answer
    D 18 Correct Answer Incorrect Answer

    Solution

    10x2 тАУ 6xy+y┬▓ тАУ 4x+4= 0 x2 -4x+4+9x2+y2-6xy=0 (x-2)2+(3x-y)2=0 When- x-2=0 x=2 3x-y =0 y=6 Now тАУ 3x+2y =3├Ч2+2x6=18.

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