Question
If x : y : z = 3 : 5 : 8, and (6x + 3z) = 168, then find the value of 2y.
Solution
Let x = ‘3a’ So, y = 3a × (5/3) = ‘5a’ And z = 3a × (8/3) = ‘8a’ ATQ; 3a × 6 + 8a × 3 = 168 Or, 18a + 24a = 168 So, 42a = 168 So, a = 4 So, required value = 2 × 5a = 40
More Algebra Questions
- If x² - 2x + 1 = 0, then find the value of (x⁴ + x⁻⁴)(x + x⁻¹).
- If x + 1/x = 3, then [x3 + (1/x3)] = ?
- If x = 10 + 2√21, then the value of √x - (1/√x)?
- If (2a + b)/(3b - 2b) = 13/2 then 'b' is what percent of 'a'?
- `sqrt(sqrt(10+sqrt(10+sqrt(10)) ... prop)` = ?
- If (x + y) = 35, then find the value of (x - 10)6 + (y - 25)6.
- If a + `1/b` = 1 and b + `1/c` =1 , then the value of c + `1/a` is
- Find ‘x’ if (x³+3x)/(3x²+1) = 189/61
- If x + y = 2 and 1/x + 1/y = 18/15, then find the value of (x3 + y3)?
- If 112 ÷28 x 22 –12 x 6 ÷ 3 +12 = z, then find the value of z.
Relevant for Exams:
