Question
Solve the inequality for real x: 3 β 2x β€ (x
+ 1)/2 < 5Solution
Treat as two inequalities. 3 β 2x β€ (x + 1)/2 Multiply both sides by 2: 6 β 4x β€ x + 1 6 β 1 β€ x + 4x 5 β€ 5x β x β₯ 1 (x + 1)/2 < 5 x + 1 < 10 β x < 9 Combined solution: 1 β€ x < 9
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