Question
If n = 6 + β13, then find the value of (n +
1/n)Β².Solution
'n' = 6 + β13
So,
1/n = 1 / (6 + β13) Γ (6 - β13)/(6 - β13)
= (6 - β13) / (36 - 13)
= 6 - β13
Required value = (6 + β13 + 6 - β13)Β² = (12)Β² = 144
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