Question
If [x + (1/x) ] = 6, then find the value of [x
3Â + (1/x 3) ].Solution
x + (1/x) = 6 On squaring both sides, We get, [x + (1/x) ]2Â = 62 Or, x2Â + (1/x2) + 2 = 36 Or, x2Â + (1/x2) = 34 ------- (I) Using a3Â + b3Â = (a + b) (a2Â + b2Â - ab) x3Â + (1/x3) = [x + (1/x) ][x2Â + (1/x2) - 1] = 6 X (34 - 1) (From equation I) = 6 X 33 = 198
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