Question
If (x 2 = 12x – 36), then find the value of
[x³ + (x⁴/36)][6 - x³]Solution
x² = 12x - 36
⇒ x² - 12x + 36 = 0
⇒ (x - 6)² = 0
⇒ x = 6
Required value = [6³ + (6⁴/36)] × [6 - 6³]
= (216 + 36) × (-210)
= 252 × (-210) = -52920
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