If a + b + c = 11, ab + bc + ca = 3 and abc = -135, then what is the value of a³ + b³ + c³ ?
=> a3 + b3 + c3 – 3abc = (a + b + c) [(a + b + c)2 – 3(ab + bc + ca)] => a3 + b3 + c3 – 3(-135) = 11 [(11)2 – 3(3)] => a3 + b3 + c3 + 405 = 1232 => a3 + b3 + c3 = 1232 – 405 => => a3 + b3 + c3 = 827
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