Question
(x + 1)2 + (y β 3) 2 + (z +
5) 2 = 0, then find the value of 2x + 3y - z.Solution
If (x + 1)2 + (y β 3) 2 + (z + 5) 2 = 0, then (x = -1), (y = 3), and (z = -5).
So,
- x + 1 = 0 β x = -1
- y - 3 = 0 β y = 3
- z + 5 = 0 β z = -5
Therefore, required value:
2(-1) + 3(3) - (-5) = -2 + 9 + 5 = 12
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