Question
The angle of elevation of the top of a tower from a
point on the ground which is 45 meters. away from the foot of the tower is 30°. The height of the tower is: ( √3=1.73)Solution
Let us consider the height of the tower as AB and the distance between the foot of the tower to the point on the ground as BC. In ΔABC, the trigonometric ratio involving AB, BC and ∠ C is tan θ. tan C = AB/BC tan 30° = AB/45 1/√3 = AB/45 AB = 45/√3 = (45 × √3) / (√3 × √3) = (45√3)/3 = 15√3 Height of tower AB = 15×1.73 m. =25.95m
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