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    Question

    The angle of elevation of the top of a tower from a

    point on the ground which is 45 meters. away from the foot of the tower is 30°. The height of the tower is: ( √3=1.73)
    A 25.95m Correct Answer Incorrect Answer
    B 22.90m Correct Answer Incorrect Answer
    C 11.45m Correct Answer Incorrect Answer
    D 12.95m Correct Answer Incorrect Answer

    Solution

    Let us consider the height of the tower as AB and the distance between the foot of the tower to the point on the ground as BC. In ΔABC, the trigonometric ratio involving AB, BC and ∠ C is tan θ. tan C = AB/BC tan 30° = AB/45 1/√3 = AB/45 AB = 45/√3 = (45 × √3) / (√3 × √3) = (45√3)/3 = 15√3 Height of tower AB = 15×1.73 m. =25.95m

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