Question
The diagonal of the square is 10 √ 2 cm. Find the
diagonal of another square whose area is triple that of the first square.Solution
Side(a) =Diagonal /√ 2 =10 √ 2 /√ 2=10cm ATQ- a2 =3×10×10 a=10√ 3 Now- Diagonal =a√ 2 =10√ 3×√ 2 =10√ 6 cm.
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