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Inner radius of the ball = 15 - 12 = 3 cm Required volume = 4/3 × π × (153 - 33) = 4/3 × π × (3375 - 27) = 4/3 × π × 3348 = 4464π
(30 × 0.80)⁴ ÷ (2160 ÷ 60)⁴ × (54 × 16)⁴ = (6 × 4)?+5
42% of 400 + 38% of 800 + ?2 = 728
√3600% of 150 + 3/5 of 360 - ? = 210
315 ÷ 9 + 23 × 3+ 22 = ?× √441
3% of 3000 x?% of 2000 = 3600
(2/7)% of 5600 ÷ √ 64 = ?
125% 0f 74÷37×48×? =192 ×√225
44.99% of 499.98 × (3.30/7.40)% of 1399.97 + 10.02 = ?
44% of 1900 + 25% of ? = 9000