The perimeter of a rectangle is 140% more than perimeter of a square of side 15 cm. If the length of rectangle is 220% more than side of square then find the difference between the area of square and the area of rectangle.
Perimeter of the square = 4 x 15 = 60 cm Perimeter of the rectangle = 60 x (240/100) = 144 cm Length of the rectangle = 15 x (320/100) = 48 cm Let the breadth of the rectangle be b cm. => 2 x (48 + b) = 144 => b = 72 – 48 => b = 24 cm Required difference = (48 x 24) - (15 x 15) = 927
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