Question
A rectangular park 60 m long and 40 m wide has two
concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2019 then the width of the road isSolution
The length of the park is 60 m The breadth of the park is 40 m The area of the lawn is 2019 m we know that, Area of a Rectangle = length × breadth Let the width of the park is x m The area of the park is ⇒ 60 × 40 = 2400 m2 The area of the road is ⇒ 60 × x + 40 × x - x2 = 2400 - 2019 ⇒ 60x + 40x - x2 = 381 ⇒ x2 - 100x + 381 = 0 ⇒ x2 - 97x - 3x + 381 = 0 ⇒ x(x - 97) - 3(x - 97) = 0 ⇒ (x - 3)(x - 97) = 0 ⇒ x = 3, 97 Since the width of the road cannot be larger than the length and the breadth ∴ The width of the road is 3 metre.
I. 49y2 + 35y + 6 = 0
II. 12x2 + 17 x + 6 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 36x + 288 = 0
Equation 2: y² - 36y + 320 = 0
I. √(17x) + √51 = 0  Â
II. √(4y) + 3 = 0
I. 4 x ² - 4 x + 1 = 0                              Â
II. 4 y ² + 4 y  + 1 = 0
...I. 64x2 - 64x + 15 Â = 0 Â Â Â Â
II. 21y2 - 13y + 2Â =0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
I. 3q² -29q +18 = 0
II. 9p² - 4 = 0
I: 3x² - 18x + 24 = 0
II: 5y² + 10y - 15 = 0
(i) 2x² + 14x - 16 = 0
(ii) y² – y – 12 = 0
The following question contains two equations as I and II.You have to solve both equations and determine the relationship between them.
I). 2a²...
