Question
A box has 80 Red, 40Blue and 40 Black Balls. 25% of Red Balls and 50% of Blue Balls are taken away, percentage of Black balls at present is
More Mensuration Questions
- Inside a square land having perimeter equal to 116 metres, leaving aside a circular land of radius 14 metres, the remaining land needs to be levelled at a ...
- If a triangle with base 7 cm has the same area as a circle with radius 7 cm, then the corresponding altitude (in cm) of the triangle is:
- Determine the volume of a cube if the total cost to paint its four walls is Rs. 1280, given that the painting rate is Rs. 5 per square meter.
- The difference between the length and breadth of a rectangle is 25 m. If its perimeter is 206 m, then its area is
- A cylindrical pencil of diameter 1.2 cm has one of its end sharpened into a conical shape of height 1.4 cm. The volume of the material removed is
- Circumference of one of the bases of a right circular cylinder is 176 cm. If height of the cylinder is 4 cm more than its radius, then find the volume (in ...
- The Height of a metallic hollow cylinder is 28 cm and the difference between its inner curved surface Area and outer curved Surface area is 66cm². If the c...
- Find the time taken by a pipe, which releases 400 m3 of water in a minute to fill an empty cylindrical tank of radius 20 m and height 14 m. [Take π = 3]
- What is the difference between (in m2) the area of a circular field of radius 21 metres and area of a rectangular piece of land having its dimensions as 18...
- A rectangle has a perimeter of 160 cm. Its breadth is 40% less than its length. Calculate the area (in cm²) of a square whose side is 20 cm shorter than th...
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)
Remaining Balls = (80 + 40 +40) – 40 = 120 Required Percentage = 40/120 ×100 = 33.33%