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Let each side of the square ‘A’ be ‘a’ cm Therefore, each side of square ‘B’ = (a + 8) cm Difference between their perimeters = 4(a + 8) – 4a = 32 cm Therefore, perimeter of the rectangle = 6 × 32 = 192 cm Let the breadth of the rectangle be ‘b’ cm According to the question, 2 × (40 + b) = 96 Or, 40 + b = 96 Or, b = 56 cm
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