New Enroll in RBI Grade B New Batch - Starts on May 21

    Question

    Each side of square ‘A’ is 8 cm less than that of

    square ‘B’. The perimeter of a rectangle is 6 times the difference of the perimeters of the two square. If the length of the rectangle is 40 cm, then find its breadth.
    A 56 cm Correct Answer Incorrect Answer
    B 50 cm Correct Answer Incorrect Answer
    C 55 cm Correct Answer Incorrect Answer
    D 58 cm Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let each side of the square ‘A’ be ‘a’ cm Therefore, each side of square ‘B’ = (a + 8) cm Difference between their perimeters = 4(a + 8) – 4a = 32 cm Therefore, perimeter of the rectangle = 6 × 32 = 192 cm Let the breadth of the rectangle be ‘b’ cm According to the question, 2 × (40 + b) = 96 Or, 40 + b = 96 Or, b = 56 cm

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