Question
Each side of square ‘A’ is 8 cm less than that of
square ‘B’. The perimeter of a rectangle is 6 times the difference of the perimeters of the two square. If the length of the rectangle is 40 cm, then find its breadth.Solution
Let each side of the square ‘A’ be ‘a’ cm Therefore, each side of square ‘B’ = (a + 8) cm Difference between their perimeters = 4(a + 8) – 4a = 32 cm Therefore, perimeter of the rectangle = 6 × 32 = 192 cm Let the breadth of the rectangle be ‘b’ cm According to the question, 2 × (40 + b) = 96 Or, 40 + b = 96 Or, b = 56 cm
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