Question
Each side of square ‘A’ is 8 cm less than that of
square ‘B’. The perimeter of a rectangle is 6 times the difference of the perimeters of the two square. If the length of the rectangle is 45 cm, then find its breadth.Solution
Let each side of the square ‘A’ be ‘a’ cm Therefore, each side of square ‘B’ = (a + 8) cm Difference between their perimeters = 4(a + 8) – 4a = 32 cm Therefore, perimeter of the rectangle = 6 × 32 = 192 cm Let the breadth of the rectangle be ‘b’ cm According to the question, 2 × (45 + b) = 96 Or, 45 + b = 96 Or, b = 51 cm
The Battle of Chausa was fought between which two historical figures?
        Consider the following statements regarding 'NatyaShastra':
       1. It is a treatise on art of drama, da...
From which space agency was the spacecraft "Psyche" launched?
Vardhamana Mahavira, a central figure in Jainism, belonged to which clan?
Which city hosted the G20 Agriculture Ministerial meeting from June 15 to 17, 2023?
Where is the first evidence of humans found in India?
Which of the following is not considered part of Sangam literature?
The title of ‘Sardar’ to Vallabhbhai Patel was given by
Which of the following personalities were the famous poetess of Indian Vedic age?
1. Lopamudra
2. Gargi
3. Gosha
4. Meera Ba...
‘Nauroj’ a nine day festival is introduced in India by which of the following king?
Relevant for Exams:
