Question
A man 3 m tall is 19 m away from a tower 22 m high.
Determine the angle of elevation of the top of the tower from the eye of the observer.Solution
In △ CDE, tan θ = CD/CE = (BD - BC)/CE = (22 - 3)/ 19 = 19/19 tan θ = 1 = tan 45 °  θ = 45 °
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