Question
A man 3 m tall is 23 m away from a tower 26 m high.
Determine the angle of elevation of the top of the tower from the eye of the observer.Solution
In â–³ CDE, tan θ = CD/CE = (BD - BC)/CE = (26 - 3)/ 23 = 23/23 tan θ = 1 = tan 45 ° θ = 45 °
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