Question
Β From a point on the ground, the angle of elevation of the top of a tower is 45 degrees. After moving 20 m away from the tower, the angle becomes 30 degrees. Find the height of the tower.
Solution
ATQ, Let the initial distance from tower be x m. Since angle = 45 degrees, height = x After moving 20 m away, distance = x + 20 Now, tan 30 = height/(x + 20) 1/β3 = x/(x + 20) x + 20 = xβ3 20 = x(β3 - 1) x = 20/(β3 - 1) = 20(β3 + 1)/2 = 10(β3 + 1) Height = x = 10(β3 + 1) m Answer: A. 10(1 + β3) m
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