Question
 From a point on the ground, the angle of elevation of
the top of a tower is 45 degrees. After moving 20 m away from the tower, the angle becomes 30 degrees. Find the height of the tower.Solution
ATQ, Let the initial distance from tower be x m. Since angle = 45 degrees, height = x After moving 20 m away, distance = x + 20 Now, tan 30 = height/(x + 20) 1/√3 = x/(x + 20) x + 20 = x√3 20 = x(√3 - 1) x = 20/(√3 - 1) = 20(√3 + 1)/2 = 10(√3 + 1) Height = x = 10(√3 + 1) m Answer: A. 10(1 + √3) m
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