Question
A man 1.5 m tall is 22.5 m away from a tower 24 m high.
Determine the angle of elevation of the top of the tower from the eye of the observer.Solution
In ⳠCDE, tan θ = CD/CE = (BD - BC)/CE = (24 - 1.5)/ 22.5 = 22.5/22.5 tan θ = 1 = tan 45 °  θ = 45 °
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