Question
The angle of elevation of an aeroplane from a point on
the ground is 60Ā°. After 12 seconds flight the elevation changes to 30Ā°, if the aeroplane is flying at a height of 1440ā3 m. find the speed of the aeroplane.Solution
Distance between two place in which angle change isĀ D = n(cotĪøā + cotĪøā) Distance = 1440ā3 (cot30Ā° + cot60Ā°) = 1440ā3 Ć ā3 - 1/ā3Ā = 1440ā3 Ć 2/ā3 = 2880 m So, distance covered by plane in 12 sec = 2880 m Speed of plane = 2880/12 = 240 m/sec.
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