Question
The top of two tower of height 48m and 60 m are
connected by wire. If the wire makes an angle of 60 ˚ with the horizontal, then the length of the wire is?Solution
AC is the wire which connected top of the tower In ∆AEC, AE = AB – CD = 12 m Sin 60˚ = AE/AC √3/2 = 12/AC AC = 24/√3 = 8√3m
[(√576 × √144) ÷ √1296]2 = ? ÷ 3
Evaluate:
(24/6) + 3 × (5 - 2)2
What will come in the place of question mark (?) in the given expression?
{(16 × 25) ÷ 32} × 12 = ? – 200
Find the value of 40 ÷ 5 of 6 × [3 ÷ 6 × (12 – 6)] – (15 ÷ 3 of 30):
Calculate the value of x2, if [(8 + 62) ÷ 4 of x + 2.5 × 5 = 42 + 20% of 10].
- What will come in place of (?), in the given expression.
144 ÷ √36 + 13² – 100 = ? √? = 120 - 102 + ∛125
360 ÷ 9 + 15 % of 200 + ? * 10 = 45 * √25
- Determine the value of following expression:
[{(148 + 32) ÷ 9}% x 1350] + 19 280 – 70 × 14 ÷ 5 = ? – 21 of 3