Question
The top of two tower of height 48m and 60 m are connected by wire. If the wire makes an angle of 60 ˚ with the horizontal, then the length of the wire is?
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AC is the wire which connected top of the tower In ∆AEC, AE = AB – CD = 12 m Sin 60˚ = AE/AC √3/2 = 12/AC AC = 24/√3 = 8√3m