Question
What is the least number which when divided by 3, 15 &
18 leave a remainder 6 in each case & it is also divisible by 12?Solution
Number which when divided by 3, 15 & 18 leaves a remainder 6 = LCM (3, 15 & 18)k+6 = 90k+6, Now it should be also divisible by 12. So (90k+6)/12 = (84k+6k+6)/12 , it means (6k+6) should be divisible by 12. So when k = 1 then it will be 6×1+6= 12 which is divisible by 12. Hence final answer = 90k+6 = 90 × 1 + 6 = 96.
1242.12 ÷ √530 + 1139.89 ÷ 14.91 = ? + 45.39
? = 25.08 + 11.99 × 24.07
40 × 55.96 ÷ 7 – 20% of 699.81 + 63 = ? - (11479.50 ÷ 7)
25.902 × 78.095 + 999.996% of 200.08 + 20.005 % of 7999.997 = ? × 15.008 × 33.009
11.67 × 50.23 + ? = 14.88% of 600.44 + 9.66 × 8.272
78% of 1450 + 26² = ? + 1323 ÷ 17
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
65.22 of 359.98% + 459.99 ÷ 23.18 = ?
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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