Question
What is the least number which when divided by 4, 6 & 8
leave a remainder 6 in each case & it is also divisible by 5?Solution
Number which when divided by 4, 6 & 8 leaves a remainder 6 = LCM (4, 6 &8)k+6 = 24k+6, Now it should be also divisible by 5. So (24k+6)/5 = (20k+4k+6)/5 , it means (4k+6) should be divisible by 5. So when k = 1 then it will be 4Ă1+6= 10 which is divisible by 5. Hence final answer = 24k+6 = 24 Ă 1 + 6 = 30.
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