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      Question

      What is the least number which when divided by 4, 6 & 8

      leave a remainder 6 in each case & it is also divisible by 5?
      A 21 Correct Answer Incorrect Answer
      B 25 Correct Answer Incorrect Answer
      C 27 Correct Answer Incorrect Answer
      D 31 Correct Answer Incorrect Answer

      Solution

      Number which when divided by 4, 6 & 8 leaves a remainder 6 = LCM (4, 6 &8)k+6 = 24k+6, Now it should be also divisible by 5. So (24k+6)/5 = (20k+4k+6)/5 , it means (4k+6) should be divisible by 5. So when k = 1 then it will be 4×1+6= 10 which is divisible by 5. Hence final answer = 24k+6 = 24 × 1 + 6 = 30.

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