Question
What is the least number which when divided by 4, 6 & 8
leave a remainder 6 in each case & it is also divisible by 5?Solution
Number which when divided by 4, 6 & 8 leaves a remainder 6 = LCM (4, 6 &8)k+6 = 24k+6, Now it should be also divisible by 5. So (24k+6)/5 = (20k+4k+6)/5 , it means (4k+6) should be divisible by 5. So when k = 1 then it will be 4×1+6= 10 which is divisible by 5. Hence final answer = 24k+6 = 24 × 1 + 6 = 30.
164, 160, 172, 136, 188, 128
120, 139, 196, 291, 420, 595
11Â Â Â 36Â Â Â Â 112Â Â Â Â 336Â Â Â Â 1011Â Â Â Â 3036
Find the wrong number in the given number series.
8, 9, 64, 25, 216, 49
Find the wrong number in the given number series.
22, 29, 50, 89, 134, 197
Find the wrong number in the given number series.
30, 46, 78, 126, 190, 278Find the wrong number in the given number series.
28, 40, 63, 98, 147, 224
In each of the following giving number series, a wrong number is given. Find out the wrong number?
3023, 3132, 3246, 3356, 3471
Find the wrong number in the given number series.
3, 6, 24, 120, 720, 5040
Find the wrong number in given number series.
14, 24, 63, 236, 1255, 6894.
Relevant for Exams:
