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    Question

    The sum and difference of the L.C.M and H.C.F of two

    numbers are 540 and 300. If one number is 60, find the other.
    A 840 Correct Answer Incorrect Answer
    B 744 Correct Answer Incorrect Answer
    C 639 Correct Answer Incorrect Answer
    D 826 Correct Answer Incorrect Answer

    Solution

    ATQ,

    Let the L.C.M and the H.C.F of the two numbers be 'a' and 'b' respectively

    Then, (a + b) = 540

    And (a - b) = 300

    So, (a + b) + (a - b) = 540 + 300 = 840

    Or, a = 840 ├╖ 2 = 420

    So, b = 540 - 420 = 120

    The product of two numbers is equal to the product of their L.C.M and H.C.FSo, required number = (420 ├Ч 120) ├╖ 60 = 840

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