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      Question

      The sum and difference of the L.C.M and H.C.F of two

      numbers are 540 and 300. If one number is 60, find the other.
      A 840 Correct Answer Incorrect Answer
      B 744 Correct Answer Incorrect Answer
      C 639 Correct Answer Incorrect Answer
      D 826 Correct Answer Incorrect Answer

      Solution

      ATQ,

      Let the L.C.M and the H.C.F of the two numbers be 'a' and 'b' respectively

      Then, (a + b) = 540

      And (a - b) = 300

      So, (a + b) + (a - b) = 540 + 300 = 840

      Or, a = 840 Γ· 2 = 420

      So, b = 540 - 420 = 120

      The product of two numbers is equal to the product of their L.C.M and H.C.FSo, required number = (420 Γ— 120) Γ· 60 = 840

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