Question
A circular wire of diameter 63 cm is folded in the shape of a rectangle whose sides are in the ratio 5:4. Find the area enclosed by the rectangle.
Solution
Using the formula, Area = lb & D = 2r and A = πr²  Radius of circular wire = 63/2 = 31.5 cm Circumference of wire = 2πr = 2 x (22/7) x 31.5 = 198 cm Let the length and breadth of rectangle be 5x & 4x cm respectively. Therefore, perimeter of rectangle = 2(5x + 4x) = 18x According to the question, 18x = 198 ⇒ x = 198/18 = 11 Therefore, length of rectangle = 5x = 5 x 11 = 55 cm Breadth of rectangle = 4x = 4 x 11 = 44 cm Area = 55 x 44 = 2420 cm²
More HCF and LCM Questions
- The LCM of two natural numbers is 12 times their HCF. If the product of given two numbers is 432, then find the LCM of the numbers.Â
- The sum of two numbers is 444 and their HCF is 37. Find all the possible pairs of such numbers?
- What is the difference between the LCM and HCF of 35, 40?
- Find the HCF of two numbers if LCM and product of those two numbers are 34 and 680 respectively.
- The least number which when divided by 7, 12, 15 and 20 leave zero remainder in each case and when divided by 26 leaves a remainder of 4 is:
- What is the least number which is a perfect square and divisible by 3, 10, 12, and 15?
- The HCF of two numbers is 8 and their LCM is 240. If one number is 40, find the other number.
- Three boys runs around a circular track and takes 24 min, 40 min and 42 min respectively to complete the one round. When do they all come relatively to the...
- Find the least common multiple of (16/20), (8/10), and (4/5).
- The LCM of two numbers is 168, and the numbers are in the ratio 4:7. Find the sum of the numbers.
Relevant for Exams:
