Question
A circular wire of diameter 63 cm is folded in the shape
of a rectangle whose sides are in the ratio 5:4. Find the area enclosed by the rectangle.Solution
Using the formula, Area = lb & D = 2r and A = πr² Radius of circular wire = 63/2 = 31.5 cm Circumference of wire = 2πr = 2 x (22/7) x 31.5 = 198 cm Let the length and breadth of rectangle be 5x & 4x cm respectively. Therefore, perimeter of rectangle = 2(5x + 4x) = 18x According to the question, 18x = 198 ⇒ x = 198/18 = 11 Therefore, length of rectangle = 5x = 5 x 11 = 55 cm Breadth of rectangle = 4x = 4 x 11 = 44 cm Area = 55 x 44 = 2420 cm²
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