Question
The HCF of two numbers is 9 and their LCM is 180. If one
of the numbers is 45, find the other number.Solution
Let the other number be x. For two numbers a and b: a × b = HCF × LCM 45 × x = 9 × 180 45 × x = 1620 x = 1620 ÷ 45 Divide numerator and denominator by 9: 1620 ÷ 9 = 180 45 ÷ 9 = 5 So, x = 180 ÷ 5 = 36
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