Question
Ratio of two numbers 6:13 and their LCM is 1950. Find
the sum of the given two numbers.Solution
Let the two numbers be '6h' and '13h', where 'h' is the HCF of the two given numbers. Product of two numbers = (Product of LCM and HCF) of the given two numbers 6h × 13h = h × 1950 Or, 78h = 1950 So, 'h' = (1950 / 78) = 25 Therefore, the required sum = 6h + 13h = 19h = 19 × 25 = 475 Hence, option c
More HCF and LCM Questions
29% of 400 + 66% of 1100 - 50% of 1200 = ?Â
{(522 – 482 ) ÷ (27 + 73)} × 35 = ?% of 175
961 × 4 ÷ 31 – 15% of 180 = ? – 73
- What will come in the place of question mark (?) in the given expression?
389 + 641 - ? = 180 X 2 (2/3) × (5/7) × (3/4) × ? = 80
{(5/8) + (4/5)} × (?/19) = 33
√3600% of 150 + 3/5 of 360 - ? = 210
4368 + 2158 – 596 - ? = 3421 + 1262
12 × 19 + 13 × 15 + 152 = ?% of 500
Simplify: (23×32) ÷6
