Question
What will be the greatest common divisor (GC
- D of (x² - 13x + 40) and (x² - 10x + 25).
Solution
(x² - 13x + 40) = x² - 8x - 5x + 40 = x(x - 8) - 5(x - 8) = (x - 8)(x - 5) x² - 10x + 25 = x² - 5x - 5x + 25 = x(x - 5) - 5(x - 5) = (x - 5)(x - 5) So, required GCD = (x - 5) Hence, option a.
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