Question
Let N be the greatest number that will divide 86, 112,
138 leaving the same remainder in each case. Then sum of the digits in N is:Solution
To find the greatest number that leaves common remainder in each case, The HCF of (112-86), (138-86), (138-112)Â = 26 In this case the number will be 26. And sum of digits will be = 8
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