Question
The LCM of two natural numbers is 10 times their HCF. If the product of given two numbers is 1000, then find the LCM of the numbers.
Solution
Let the HCF of the number be 'H'. So, LCM = 10H Product of two numbers = Product of their HCF and LCM So, 10H × H = 1000 Or, H² = 100 Or, H = 10 or H = –10 Since, HCF cannot be negative. So, H = 10 Therefore, LCM = 10 × 10 = 100
More HCF and LCM Questions
- What is the Highest Common Factor of 54, 162 and 270?
- The ratio of two number is 6 : 5 and their HCF is 15. So find and their LCM?
- The HCF of two numbers is 17. If their product is 867, then how many such pairs exist?
- If the product of two numbers is 96 and their HCF is 8, find the LCM of the given two numbers.
- Find the largest four-digit number which when divided by each of 18, 21 and 24 leaves a remainder of 7.
- The greatest number, which when subtracted from 5260, gives a number exactly divisible by each of 12, 16, 20 and 25, is:
- If the product of two numbers is 108 and their HCF is 6, then find the LCM of the given two numbers.
- What are the Highest Common Factor and Lowest Common Multiple of 6, 72, 120?
- Let N be the greatest number that will divide 78, 109, 140 leaving the same remainder in each case. Then sum of the digits in N is:
- The Highest Common Factor (HCF) and Least Common Multiple (LCM) of two numbers, X and Y, are given as 8 and 80, respectively. Additionally, the difference ...