Question
Determine the total count of prime factors in the
product: 217 x 197 x 107Solution
For a number (N) whose prime factorization is of the form, N = ap X bq X cr, where 'a', 'b' and 'c' are prime numbers, then total number of prime factors of the number 'N' will be = (p + q + r)
Given expression: 217 X 197 X 107 = 37 X 77 X 197 X 27 X 57
Therefore, total number of prime factors = (7 + 7 + 7 + 7 + 7) = 35
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