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      Question

      The length of a width is 20 cm and the side of a square

      is 24 cm less than the length and width of the rectangle. If perimeter of the rectangle is 30 cm more than the perimeter of the square, then find the diagonal of the square.
      A 9тИЪ2 Correct Answer Incorrect Answer
      B 10тИЪ2 Correct Answer Incorrect Answer
      C 5тИЪ2 Correct Answer Incorrect Answer
      D 11тИЪ2 Correct Answer Incorrect Answer
      E 13тИЪ2 Correct Answer Incorrect Answer

      Solution

      Let the length of the rectangle be тАШxтАЩ cm. And side of the square = [(x + 20) тАУ 24] = (x тАУ 4) cm According to the question, => 2(x + 20) тАУ 4(x - 4) = 30 => 2x + 40 тАУ 4x + 16 = 30 => 2x = 26 => x = 13 Side of the square = (x тАУ 4) = 9 Diagonal of square = 9тИЪ2 cm

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