Question
The greatest number of four digits which when divided by
6, 8, 10 leave remainders 3, 5, 7 respectively is:Solution
The difference between divisor and the corresponding remainder is equal (i.e 3). LCM of 6, 8 and 10 = 120 Largest 4-digit number = 9999 After dividing 9999 by 120 we will get the remainder as 39. Therefore, the number divisible by 120 = 9999 – 39 = 9960 If 3 is subtracted from the number 9960 the resulting number will follow the condition in the question and that number is 9957.
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