Question
The least number which when divided by 4, 8, 10 and 12
leave zero remainder in each case and when divided by 13 leaves a remainder of 9 is:Solution
LCM of 4, 8, 10 and 12Ā = 120 Required number = 120, because it is exactly divisible by 4, 8, 10 and 12Ā and it leaves remainder 9 when divided by 13.
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