Question
Find out the sum of digits of largest number that leaves
same remainder when it divides 12006, 6006, 5506 and 10006.Solution
To leave same remainder the difference between two dividends must be divisible by the divisor Taking difference of the numbers in descending order ⇒ 12006 – 11006 = 1000 ⇒ 11006 – 6006 = 5000 ⇒ 6006 – 5506 = 500 Each interval must be divisible by the divisor. ⇒ We need HCF of these numbers 1000, 5000 and 500 is 500 ∴ sum of digits = 5 + 0 + 0 = 5
?% of (168 ÷ 8 × 20) = 126
20% of 1500 – 75% of 200 = 125% of ?
Find the value of 16 X [(8 - 5) of 12 ÷ 4].
√196 + (0.25 × 144) + 19 = ? + 72
22 * 6 + 45% of 90 + 65% of 180 = ?
52% of 400 + √(?) = 60% of 600 - 25% of 400
(25 × 12 + 30 × 8 – 22 × 10) = ?
What will come in the place of question mark (?) in the given expression?
(240% of 175 ÷ √16) X 6 + 80% of 400 = ?3 + 179 + 42
What will come in the place of question mark (?) in the given expression?
(144 × 16 ÷ 12) × 6 = ?
808 ÷ (128)1/7 + 482 = 4 × ? + 846
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