Question
O is the circum centre of the isosceles ∆ ABC. Given
that AB = AC = 5 cm and BC = 6 cm. The radius of the circle isSolution
Use PGT in ∆OBD r2 - (4 – r)2 = 9 (r+4-r)(r-4+r) = 9 4(2r – 4) = 9 2r – 4 = 9/4 2r = 9/4 + 4 = 25/4 r = 25/8 => 3.125 cm
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